# How do you graph #y=x^2+4x+6#?

##### 1 Answer

Aug 8, 2015

Graph

#### Explanation:

To graph a parabola, fins a few critical points, such as: vertex, axis of symmetry, y intercept and x-intercepts.

x-coordinate of vertex:

(y-coordinate of vertex: y = f(-2) = 4 - 8 + 6 = 2

Axis of symmetry: x = -2

y-intercept --> Make x = 0 --> y = 6

x-intercepts --> Solve y = 0.

D = 16 - 24 = - 8 < 0.

There are no x-intercepts. The parabola is completely above the x-axis.

Since a> 0, the parabola opens upward, there is a min at vertex.

graph{x^2 + 4x + 6 [-10, 10, -5, 5]}